Введение в модель данных SQL

WITH RECURSIVE PARTS


WITH RECURSIVE PARTS (PART_NUMBER,
NUMBER_OF_PARTS, COST) AS
(SELECT CONTAINED_PART, 1, 0.00 (a)
FROM CAR
WHERE CONTAINING_PART = ''
UNION ALL
SELECT CAR.CONTAINED_PART, CAR.NUMBER_OF_PARTS,
CAR.NUMBER_OF_PARTS * CAR.PART_COST
FROM CAR, PARTS
WHERE PARTS.PART_NUMBER = CAR.CONTAINING_PART)
SELECT PART_NUMBER, SUM(NUMBER_OF PARTS),
SUM(COST) (b)
FROM PARTS
GROUP BY PART_NUMBER;

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