Введение в модель данных SQL

PART_COST FROM CAR, PARTS WHERE


WITH RECURSIVE PARTS (PART_NUMBER, NUMBER_OF_PARTS, COST) AS (SELECT CONTAINED_PART, 1, 0.00 (a) FROM CAR WHERE CONTAINING_PART = '' UNION ALL SELECT CAR.CONTAINED_PART, CAR.NUMBER_OF_PARTS, CAR.NUMBER_OF_PARTS * CAR. PART_COST FROM CAR, PARTS WHERE PARTS.PART_NUMBER = CAR.CONTAINING_PART) SELECT PART_NUMBER, SUM(NUMBER_OF PARTS), SUM(COST) (b) FROM PARTS GROUP BY PART_NUMBER;
Пример 16.3.
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